Base | Representation |
---|---|
bin | 111110101010100001001101… |
… | …1011101111101011111110010 |
3 | 2200021122100111102201011020211 |
4 | 1331111002123131331133302 |
5 | 1034221341213443101002 |
6 | 5232150253203054334 |
7 | 224046665533435123 |
oct | 17525023335753762 |
9 | 2607570442634224 |
10 | 551201531222002 |
11 | 14a6a2290642781 |
12 | 519a26716713aa |
13 | 1a8741099a5b8b |
14 | 9a1842169c04a |
15 | 43ad03b8addd7 |
hex | 1f5509b77d7f2 |
551201531222002 has 64 divisors (see below), whose sum is σ = 865429062027264. Its totient is φ = 262800927164160.
The previous prime is 551201531221981. The next prime is 551201531222029. The reversal of 551201531222002 is 200222135102155.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149094272218 + ... + 149094275914.
It is an arithmetic number, because the mean of its divisors is an integer number (13522329094176).
Almost surely, 2551201531222002 is an apocalyptic number.
551201531222002 is a deficient number, since it is larger than the sum of its proper divisors (314227530805262).
551201531222002 is a wasteful number, since it uses less digits than its factorization.
551201531222002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9463.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 551201531222002 its reverse (200222135102155), we get a palindrome (751423666324157).
The spelling of 551201531222002 in words is "five hundred fifty-one trillion, two hundred one billion, five hundred thirty-one million, two hundred twenty-two thousand, two".
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