Base | Representation |
---|---|
bin | 101000000110110100011… |
… | …0000001110001000000001 |
3 | 201111221221201202001202120 |
4 | 1100031220300032020001 |
5 | 1210302441312341001 |
6 | 15420134151034453 |
7 | 1106146316164401 |
oct | 120155060161001 |
9 | 21457851661676 |
10 | 5512200512001 |
11 | 1835790539227 |
12 | 75037496ba29 |
13 | 30ca4ba7cbc1 |
14 | 150b130a0801 |
15 | 985b94d1236 |
hex | 50368c0e201 |
5512200512001 has 4 divisors (see below), whose sum is σ = 7349600682672. Its totient is φ = 3674800341332.
The previous prime is 5512200511981. The next prime is 5512200512003. The reversal of 5512200512001 is 1002150022155.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5512200512001 - 25 = 5512200511969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5512200512003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918700085331 + ... + 918700085336.
It is an arithmetic number, because the mean of its divisors is an integer number (1837400170668).
Almost surely, 25512200512001 is an apocalyptic number.
It is an amenable number.
5512200512001 is a deficient number, since it is larger than the sum of its proper divisors (1837400170671).
5512200512001 is a wasteful number, since it uses less digits than its factorization.
5512200512001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1837400170670.
The product of its (nonzero) digits is 1000, while the sum is 24.
Adding to 5512200512001 its reverse (1002150022155), we get a palindrome (6514350534156).
The spelling of 5512200512001 in words is "five trillion, five hundred twelve billion, two hundred million, five hundred twelve thousand, one".
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