Base | Representation |
---|---|
bin | 101000000110110101001… |
… | …0010011101110101000001 |
3 | 201111222000112012112012102 |
4 | 1100031222102131311001 |
5 | 1210303014411011213 |
6 | 15420140511040145 |
7 | 1106150051121245 |
oct | 120155222356501 |
9 | 21458015175172 |
10 | 5512226266433 |
11 | 18357a4029987 |
12 | 750381510055 |
13 | 30ca541c9603 |
14 | 150b16686425 |
15 | 985bb8bc158 |
hex | 5036a49dd41 |
5512226266433 has 2 divisors, whose sum is σ = 5512226266434. Its totient is φ = 5512226266432.
The previous prime is 5512226266427. The next prime is 5512226266457. The reversal of 5512226266433 is 3346626222155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5182511439169 + 329714827264 = 2276513^2 + 574208^2 .
It is a cyclic number.
It is not a de Polignac number, because 5512226266433 - 28 = 5512226266177 is a prime.
It is not a weakly prime, because it can be changed into another prime (5512226286433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756113133216 + 2756113133217.
It is an arithmetic number, because the mean of its divisors is an integer number (2756113133217).
Almost surely, 25512226266433 is an apocalyptic number.
It is an amenable number.
5512226266433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5512226266433 is an equidigital number, since it uses as much as digits as its factorization.
5512226266433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400, while the sum is 47.
The spelling of 5512226266433 in words is "five trillion, five hundred twelve billion, two hundred twenty-six million, two hundred sixty-six thousand, four hundred thirty-three".
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