Base | Representation |
---|---|
bin | 101000000110111101101… |
… | …1101101111110111111001 |
3 | 201111222202121110002100121 |
4 | 1100031323131233313321 |
5 | 1210304112143432401 |
6 | 15420225243333241 |
7 | 1106160150410434 |
oct | 120157335576771 |
9 | 21458677402317 |
10 | 5512514436601 |
11 | 1835931763447 |
12 | 750441b21221 |
13 | 30ca9bb149c3 |
14 | 150b42a5a81b |
15 | 985d6d40ca1 |
hex | 5037b76fdf9 |
5512514436601 has 2 divisors, whose sum is σ = 5512514436602. Its totient is φ = 5512514436600.
The previous prime is 5512514436529. The next prime is 5512514436643. The reversal of 5512514436601 is 1066344152155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5089332962025 + 423181474576 = 2255955^2 + 650524^2 .
It is a cyclic number.
It is not a de Polignac number, because 5512514436601 - 221 = 5512512339449 is a prime.
It is not a weakly prime, because it can be changed into another prime (5512514436691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756257218300 + 2756257218301.
It is an arithmetic number, because the mean of its divisors is an integer number (2756257218301).
Almost surely, 25512514436601 is an apocalyptic number.
It is an amenable number.
5512514436601 is a deficient number, since it is larger than the sum of its proper divisors (1).
5512514436601 is an equidigital number, since it uses as much as digits as its factorization.
5512514436601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 43.
Adding to 5512514436601 its reverse (1066344152155), we get a palindrome (6578858588756).
The spelling of 5512514436601 in words is "five trillion, five hundred twelve billion, five hundred fourteen million, four hundred thirty-six thousand, six hundred one".
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