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55130025241 = 311778387911
BaseRepresentation
bin110011010110000000…
…010110110100011001
312021022002212110021201
4303112000112310121
51400401241301431
641154255434201
73661113324364
oct632600266431
9167262773251
1055130025241
1121420509a35
12a826b25961
135277825715
14294db9b0db
151679e32461
hexcd6016d19

55130025241 has 4 divisors (see below), whose sum is σ = 56908413184. Its totient is φ = 53351637300.

The previous prime is 55130025221. The next prime is 55130025257. The reversal of 55130025241 is 14252003155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55130025241 - 227 = 54995807513 is a prime.

It is not an unprimeable number, because it can be changed into a prime (55130025221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 889193925 + ... + 889193986.

It is an arithmetic number, because the mean of its divisors is an integer number (14227103296).

Almost surely, 255130025241 is an apocalyptic number.

It is an amenable number.

55130025241 is a deficient number, since it is larger than the sum of its proper divisors (1778387943).

55130025241 is a wasteful number, since it uses less digits than its factorization.

55130025241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1778387942.

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 55130025241 its reverse (14252003155), we get a palindrome (69382028396).

The spelling of 55130025241 in words is "fifty-five billion, one hundred thirty million, twenty-five thousand, two hundred forty-one".

Divisors: 1 31 1778387911 55130025241