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55131314220211 = 110714979795341
BaseRepresentation
bin11001000100100010000100…
…11001100110110010110011
321020012111120002010221101111
430202101002121212302303
524211232412420021321
6313130550501214151
714420051234555365
oct1442210231466263
9236174502127344
1055131314220211
1116626071674889
126224999701357
13249bb25a35458
14d88526bdcd35
1565915a7935e1
hex322442666cb3

55131314220211 has 4 divisors (see below), whose sum is σ = 55136294026624. Its totient is φ = 55126334413800.

The previous prime is 55131314220149. The next prime is 55131314220223. The reversal of 55131314220211 is 11202241313155.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55131314220211 - 219 = 55131313695923 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55131314220811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2489886600 + ... + 2489908741.

It is an arithmetic number, because the mean of its divisors is an integer number (13784073506656).

Almost surely, 255131314220211 is an apocalyptic number.

55131314220211 is a deficient number, since it is larger than the sum of its proper divisors (4979806413).

55131314220211 is a wasteful number, since it uses less digits than its factorization.

55131314220211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4979806412.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 55131314220211 its reverse (11202241313155), we get a palindrome (66333555533366).

The spelling of 55131314220211 in words is "fifty-five trillion, one hundred thirty-one billion, three hundred fourteen million, two hundred twenty thousand, two hundred eleven".

Divisors: 1 11071 4979795341 55131314220211