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551343049403 is a prime number
BaseRepresentation
bin10000000010111101001…
…10110100101010111011
31221201010001012212021212
420001132212310222323
533013122310040103
61101141122553335
754555536411126
oct10013646645273
91851101185255
10551343049403
111a2906861433
128aa2b80884b
133ccb7219293
141c98407d3bd
15e51d36d7d8
hex805e9b4abb

551343049403 has 2 divisors, whose sum is σ = 551343049404. Its totient is φ = 551343049402.

The previous prime is 551343049399. The next prime is 551343049417. The reversal of 551343049403 is 304940343155.

551343049403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 551343049403 - 22 = 551343049399 is a prime.

It is not a weakly prime, because it can be changed into another prime (551343049483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275671524701 + 275671524702.

It is an arithmetic number, because the mean of its divisors is an integer number (275671524702).

Almost surely, 2551343049403 is an apocalyptic number.

551343049403 is a deficient number, since it is larger than the sum of its proper divisors (1).

551343049403 is an equidigital number, since it uses as much as digits as its factorization.

551343049403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 551343049403 in words is "five hundred fifty-one billion, three hundred forty-three million, forty-nine thousand, four hundred three".