Base | Representation |
---|---|
bin | 11001000100100111101011… |
… | …11000111100000001101001 |
3 | 21020012210022221111121112220 |
4 | 30202103311320330001221 |
5 | 24211310044320232210 |
6 | 313132205352424253 |
7 | 14420215661521113 |
oct | 1442236570740151 |
9 | 236183287447486 |
10 | 55134325555305 |
11 | 16627377477477 |
12 | 622549a0a8089 |
13 | 249c1b5888139 |
14 | d88730b163b3 |
15 | 659284d25c70 |
hex | 3224f5e3c069 |
55134325555305 has 16 divisors (see below), whose sum is σ = 88218614471424. Its totient is φ = 29403742435200.
The previous prime is 55134325555261. The next prime is 55134325555313. The reversal of 55134325555305 is 50355552343155.
It is not a de Polignac number, because 55134325555305 - 213 = 55134325547113 is a prime.
It is a super-2 number, since 2×551343255553052 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76579396 + ... + 77296005.
It is an arithmetic number, because the mean of its divisors is an integer number (5513663404464).
Almost surely, 255134325555305 is an apocalyptic number.
It is an amenable number.
55134325555305 is a deficient number, since it is larger than the sum of its proper divisors (33084288916119).
55134325555305 is a wasteful number, since it uses less digits than its factorization.
55134325555305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153899296.
The product of its (nonzero) digits is 16875000, while the sum is 51.
The spelling of 55134325555305 in words is "fifty-five trillion, one hundred thirty-four billion, three hundred twenty-five million, five hundred fifty-five thousand, three hundred five".
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