Base | Representation |
---|---|
bin | 110011010110100111… |
… | …101011011010110001 |
3 | 12021022211021011012012 |
4 | 303112213223122301 |
5 | 1400411411130413 |
6 | 41155304412305 |
7 | 3661300046006 |
oct | 632647533261 |
9 | 167284234165 |
10 | 55140333233 |
11 | 2142630a537 |
12 | a82a477095 |
13 | 52799c451b |
14 | 29512c18ad |
15 | 167acbb7a8 |
hex | cd69eb6b1 |
55140333233 has 4 divisors (see below), whose sum is σ = 56422666608. Its totient is φ = 53857999860.
The previous prime is 55140333217. The next prime is 55140333251. The reversal of 55140333233 is 33233304155.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55140333233 - 24 = 55140333217 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 55140333233.
It is not an unprimeable number, because it can be changed into a prime (55140333203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641166623 + ... + 641166708.
It is an arithmetic number, because the mean of its divisors is an integer number (14105666652).
Almost surely, 255140333233 is an apocalyptic number.
It is an amenable number.
55140333233 is a deficient number, since it is larger than the sum of its proper divisors (1282333375).
55140333233 is a wasteful number, since it uses less digits than its factorization.
55140333233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1282333374.
The product of its (nonzero) digits is 48600, while the sum is 32.
Adding to 55140333233 its reverse (33233304155), we get a palindrome (88373637388).
The spelling of 55140333233 in words is "fifty-five billion, one hundred forty million, three hundred thirty-three thousand, two hundred thirty-three".
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