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55142033497 is a prime number
BaseRepresentation
bin110011010110101110…
…001010100001011001
312021022221110112111221
4303112232022201121
51400412330032442
641155405052041
73661320360025
oct632656124131
9167287415457
1055142033497
1121427270a11
12a82ab57021
13527a16b3b5
142951605385
15167b005467
hexcd6b8a859

55142033497 has 2 divisors, whose sum is σ = 55142033498. Its totient is φ = 55142033496.

The previous prime is 55142033477. The next prime is 55142033519. The reversal of 55142033497 is 79433024155.

55142033497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31566273561 + 23575759936 = 177669^2 + 153544^2 .

It is a cyclic number.

It is not a de Polignac number, because 55142033497 - 223 = 55133644889 is a prime.

It is a super-3 number, since 3×551420334973 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (55142033437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27571016748 + 27571016749.

It is an arithmetic number, because the mean of its divisors is an integer number (27571016749).

Almost surely, 255142033497 is an apocalyptic number.

It is an amenable number.

55142033497 is a deficient number, since it is larger than the sum of its proper divisors (1).

55142033497 is an equidigital number, since it uses as much as digits as its factorization.

55142033497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 453600, while the sum is 43.

The spelling of 55142033497 in words is "fifty-five billion, one hundred forty-two million, thirty-three thousand, four hundred ninety-seven".