Base | Representation |
---|---|
bin | 11001000100111001111000… |
… | …11010111010100010000001 |
3 | 21020020201120001120222100001 |
4 | 30202130330122322202001 |
5 | 24211440103243124133 |
6 | 313140503235200001 |
7 | 14421013113661111 |
oct | 1442347432724201 |
9 | 236221501528301 |
10 | 55144098801793 |
11 | 16630532196191 |
12 | 6227367146001 |
13 | 24a00b25b1c21 |
14 | d88dbaad1041 |
15 | 659657d4287d |
hex | 32273c6ba881 |
55144098801793 has 2 divisors, whose sum is σ = 55144098801794. Its totient is φ = 55144098801792.
The previous prime is 55144098801763. The next prime is 55144098801797. The reversal of 55144098801793 is 39710889044155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29961687270529 + 25182411531264 = 5473727^2 + 5018208^2 .
It is a cyclic number.
It is not a de Polignac number, because 55144098801793 - 237 = 55006659848321 is a prime.
It is not a weakly prime, because it can be changed into another prime (55144098801797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27572049400896 + 27572049400897.
It is an arithmetic number, because the mean of its divisors is an integer number (27572049400897).
Almost surely, 255144098801793 is an apocalyptic number.
It is an amenable number.
55144098801793 is a deficient number, since it is larger than the sum of its proper divisors (1).
55144098801793 is an equidigital number, since it uses as much as digits as its factorization.
55144098801793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43545600, while the sum is 64.
The spelling of 55144098801793 in words is "fifty-five trillion, one hundred forty-four billion, ninety-eight million, eight hundred one thousand, seven hundred ninety-three".
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