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551523522250121 is a prime number
BaseRepresentation
bin111110101100110111001001…
…1101000010000010110001001
32200022210010121112122011100212
41331121232103220100112021
51034242130133144000441
65232554224112210505
7224112155011141211
oct17531562350202611
92608703545564325
10551523522250121
1114a8068a3137983
1251a34b53839a35
131a8985a2834b55
149a29c492c7241
1543b65d49c7eeb
hex1f59b93a10589

551523522250121 has 2 divisors, whose sum is σ = 551523522250122. Its totient is φ = 551523522250120.

The previous prime is 551523522250109. The next prime is 551523522250157. The reversal of 551523522250121 is 121052225325155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 298076772010000 + 253446750240121 = 17264900^2 + 15920011^2 .

It is a cyclic number.

It is not a de Polignac number, because 551523522250121 - 234 = 551506342380937 is a prime.

It is not a weakly prime, because it can be changed into another prime (551523522250721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275761761125060 + 275761761125061.

It is an arithmetic number, because the mean of its divisors is an integer number (275761761125061).

Almost surely, 2551523522250121 is an apocalyptic number.

It is an amenable number.

551523522250121 is a deficient number, since it is larger than the sum of its proper divisors (1).

551523522250121 is an equidigital number, since it uses as much as digits as its factorization.

551523522250121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 300000, while the sum is 41.

Adding to 551523522250121 its reverse (121052225325155), we get a palindrome (672575747575276).

The spelling of 551523522250121 in words is "five hundred fifty-one trillion, five hundred twenty-three billion, five hundred twenty-two million, two hundred fifty thousand, one hundred twenty-one".