Base | Representation |
---|---|
bin | 110011010111011010… |
… | …010101100000000001 |
3 | 12021100202020211100001 |
4 | 303113122111200001 |
5 | 1400423311102201 |
6 | 41200501200001 |
7 | 3661520654650 |
oct | 632732254001 |
9 | 167322224301 |
10 | 55153612801 |
11 | 2143285a691 |
12 | a832a00001 |
13 | 527c693a61 |
14 | 2952d7b197 |
15 | 167c041301 |
hex | cd7695801 |
55153612801 has 8 divisors (see below), whose sum is σ = 63071455040. Its totient is φ = 47245459248.
The previous prime is 55153612783. The next prime is 55153612819. The reversal of 55153612801 is 10821635155.
It is an interprime number because it is at equal distance from previous prime (55153612783) and next prime (55153612819).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55153612801 - 213 = 55153604609 is a prime.
It is a super-3 number, since 3×551536128013 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55153612001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2409966 + ... + 2432743.
It is an arithmetic number, because the mean of its divisors is an integer number (7883931880).
Almost surely, 255153612801 is an apocalyptic number.
It is an amenable number.
55153612801 is a deficient number, since it is larger than the sum of its proper divisors (7917842239).
55153612801 is a wasteful number, since it uses less digits than its factorization.
55153612801 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4844343.
The product of its (nonzero) digits is 36000, while the sum is 37.
The spelling of 55153612801 in words is "fifty-five billion, one hundred fifty-three million, six hundred twelve thousand, eight hundred one".
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