Base | Representation |
---|---|
bin | 11001000110001001111001… |
… | …00011001100010110101011 |
3 | 21020101211102110001200100021 |
4 | 30203010330203030112223 |
5 | 24213141034431114112 |
6 | 313212325302221311 |
7 | 14424063363424366 |
oct | 1443047443142653 |
9 | 236354373050307 |
10 | 55187050644907 |
11 | 16647773402695 |
12 | 6233753724837 |
13 | 24a41690874cc |
14 | d8b0d332b0dd |
15 | 65a81da59907 |
hex | 32313c8cc5ab |
55187050644907 has 2 divisors, whose sum is σ = 55187050644908. Its totient is φ = 55187050644906.
The previous prime is 55187050644889. The next prime is 55187050644923. The reversal of 55187050644907 is 70944605078155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55187050644907 - 215 = 55187050612139 is a prime.
It is a super-2 number, since 2×551870506449072 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55187050644997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27593525322453 + 27593525322454.
It is an arithmetic number, because the mean of its divisors is an integer number (27593525322454).
Almost surely, 255187050644907 is an apocalyptic number.
55187050644907 is a deficient number, since it is larger than the sum of its proper divisors (1).
55187050644907 is an equidigital number, since it uses as much as digits as its factorization.
55187050644907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42336000, while the sum is 61.
The spelling of 55187050644907 in words is "fifty-five trillion, one hundred eighty-seven billion, fifty million, six hundred forty-four thousand, nine hundred seven".
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