Base | Representation |
---|---|
bin | 10000000100001011110… |
… | …10001111011110000011 |
3 | 1221202210222222221200111 |
4 | 20002011322033132003 |
5 | 33021000111420311 |
6 | 1101330400132151 |
7 | 54611064263542 |
oct | 10020572173603 |
9 | 1852728887614 |
10 | 552002451331 |
11 | 1a3114aa1901 |
12 | 8ab94607057 |
13 | 40090a12836 |
14 | 1ca0788a159 |
15 | e55b1c1d21 |
hex | 8085e8f783 |
552002451331 has 4 divisors (see below), whose sum is σ = 552121140664. Its totient is φ = 551883762000.
The previous prime is 552002451277. The next prime is 552002451379. The reversal of 552002451331 is 133154200255.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 552002451331 - 215 = 552002418563 is a prime.
It is a super-2 number, since 2×5520024513312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 552002451293 and 552002451302.
It is not an unprimeable number, because it can be changed into a prime (552002451131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59337690 + ... + 59346991.
It is an arithmetic number, because the mean of its divisors is an integer number (138030285166).
Almost surely, 2552002451331 is an apocalyptic number.
552002451331 is a deficient number, since it is larger than the sum of its proper divisors (118689333).
552002451331 is a wasteful number, since it uses less digits than its factorization.
552002451331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118689332.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 552002451331 its reverse (133154200255), we get a palindrome (685156651586).
The spelling of 552002451331 in words is "five hundred fifty-two billion, two million, four hundred fifty-one thousand, three hundred thirty-one".
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