Base | Representation |
---|---|
bin | 11001000110110110111001… |
… | …01000111010001001111011 |
3 | 21020111010210020122212101221 |
4 | 30203123130220322021323 |
5 | 24214040030100144032 |
6 | 313231402541452511 |
7 | 14425610200045102 |
oct | 1443333450721173 |
9 | 236433706585357 |
10 | 55211211334267 |
11 | 16656a4149915a |
12 | 6238376b71137 |
13 | 24a6519755cc1 |
14 | d8c346035039 |
15 | 65b284bdc597 |
hex | 3236dca3a27b |
55211211334267 has 2 divisors, whose sum is σ = 55211211334268. Its totient is φ = 55211211334266.
The previous prime is 55211211334189. The next prime is 55211211334289. The reversal of 55211211334267 is 76243311211255.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55211211334267 is a prime.
It is not a weakly prime, because it can be changed into another prime (55211211331267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27605605667133 + 27605605667134.
It is an arithmetic number, because the mean of its divisors is an integer number (27605605667134).
Almost surely, 255211211334267 is an apocalyptic number.
55211211334267 is a deficient number, since it is larger than the sum of its proper divisors (1).
55211211334267 is an equidigital number, since it uses as much as digits as its factorization.
55211211334267 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 302400, while the sum is 43.
The spelling of 55211211334267 in words is "fifty-five trillion, two hundred eleven billion, two hundred eleven million, three hundred thirty-four thousand, two hundred sixty-seven".
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