Base | Representation |
---|---|
bin | 11001000110111010110111… |
… | …01101110100111110110001 |
3 | 21020111100021211101111001012 |
4 | 30203131123231310332301 |
5 | 24214103411343031400 |
6 | 313232354301520305 |
7 | 14426014055522543 |
oct | 1443353355647661 |
9 | 236440254344035 |
10 | 55213343330225 |
11 | 166579359a0293 |
12 | 6238870b73095 |
13 | 24a6799367482 |
14 | d8c4a924d693 |
15 | 65b35be74d35 |
hex | 32375bb74fb1 |
55213343330225 has 6 divisors (see below), whose sum is σ = 68464545729510. Its totient is φ = 44170674664160.
The previous prime is 55213343330183. The next prime is 55213343330251. The reversal of 55213343330225 is 52203334331255.
It can be written as a sum of positive squares in 3 ways, for example, as 5899297749409 + 49314045580816 = 2428847^2 + 7022396^2 .
It is not a de Polignac number, because 55213343330225 - 212 = 55213343326129 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1104266866580 + ... + 1104266866629.
It is an arithmetic number, because the mean of its divisors is an integer number (11410757621585).
Almost surely, 255213343330225 is an apocalyptic number.
It is an amenable number.
55213343330225 is a deficient number, since it is larger than the sum of its proper divisors (13251202399285).
55213343330225 is a wasteful number, since it uses less digits than its factorization.
55213343330225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2208533733219 (or 2208533733214 counting only the distinct ones).
The product of its (nonzero) digits is 972000, while the sum is 41.
The spelling of 55213343330225 in words is "fifty-five trillion, two hundred thirteen billion, three hundred forty-three million, three hundred thirty thousand, two hundred twenty-five".
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