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5521544412113 is a prime number
BaseRepresentation
bin101000001011001010110…
…1100010111101111010001
3201112212001220221101001002
41100112111230113233101
51210431110332141423
615424321255151345
71106630006055602
oct120262554275721
921485056841032
105521544412113
111839745968724
12752142075555
133108aa85ba92
1415135c035da9
159896498e228
hex50595b17bd1

5521544412113 has 2 divisors, whose sum is σ = 5521544412114. Its totient is φ = 5521544412112.

The previous prime is 5521544412053. The next prime is 5521544412157. The reversal of 5521544412113 is 3112144451255.

5521544412113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5427888827089 + 93655585024 = 2329783^2 + 306032^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5521544412113 is a prime.

It is a super-2 number, since 2×55215444121132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5521544412313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2760772206056 + 2760772206057.

It is an arithmetic number, because the mean of its divisors is an integer number (2760772206057).

Almost surely, 25521544412113 is an apocalyptic number.

It is an amenable number.

5521544412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5521544412113 is an equidigital number, since it uses as much as digits as its factorization.

5521544412113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96000, while the sum is 38.

Adding to 5521544412113 its reverse (3112144451255), we get a palindrome (8633688863368).

The spelling of 5521544412113 in words is "five trillion, five hundred twenty-one billion, five hundred forty-four million, four hundred twelve thousand, one hundred thirteen".