Base | Representation |
---|---|
bin | 11001000111001111000111… |
… | …00110011000011110001011 |
3 | 21020112101100100121122120222 |
4 | 30203213203212120132023 |
5 | 24214243142012430121 |
6 | 313241353032540255 |
7 | 14426550323361110 |
oct | 1443474346303613 |
9 | 236471310548528 |
10 | 55224213014411 |
11 | 16661503610961 |
12 | 623a9a525168b |
13 | 24a780c29566c |
14 | d8cc1aaba907 |
15 | 65b7963720ab |
hex | 3239e399878b |
55224213014411 has 16 divisors (see below), whose sum is σ = 65857777920000. Its totient is φ = 45276766722528.
The previous prime is 55224213014309. The next prime is 55224213014417. The reversal of 55224213014411 is 11441031242255.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55224213014411 is a prime.
It is a super-3 number, since 3×552242130144113 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55224213014417) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36152765 + ... + 37649313.
It is an arithmetic number, because the mean of its divisors is an integer number (4116111120000).
Almost surely, 255224213014411 is an apocalyptic number.
55224213014411 is a deficient number, since it is larger than the sum of its proper divisors (10633564905589).
55224213014411 is a wasteful number, since it uses less digits than its factorization.
55224213014411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1725778.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 55224213014411 its reverse (11441031242255), we get a palindrome (66665244256666).
The spelling of 55224213014411 in words is "fifty-five trillion, two hundred twenty-four billion, two hundred thirteen million, fourteen thousand, four hundred eleven".
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