Base | Representation |
---|---|
bin | 11001000111011101000101… |
… | …01000111100000110001011 |
3 | 21020120002201001100111002001 |
4 | 30203232202220330012023 |
5 | 24214404022023201141 |
6 | 313245033153451431 |
7 | 14430234224142256 |
oct | 1443564250740613 |
9 | 236502631314061 |
10 | 55231713100171 |
11 | 16664702180343 |
12 | 6240338b70b77 |
13 | 24a843608372a |
14 | d8d32cc1209d |
15 | 65ba84a1ea31 |
hex | 323ba2a3c18b |
55231713100171 has 2 divisors, whose sum is σ = 55231713100172. Its totient is φ = 55231713100170.
The previous prime is 55231713100139. The next prime is 55231713100219. The reversal of 55231713100171 is 17100131713255.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55231713100171 - 25 = 55231713100139 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55231713100171.
It is not a weakly prime, because it can be changed into another prime (55231713100111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27615856550085 + 27615856550086.
It is an arithmetic number, because the mean of its divisors is an integer number (27615856550086).
Almost surely, 255231713100171 is an apocalyptic number.
55231713100171 is a deficient number, since it is larger than the sum of its proper divisors (1).
55231713100171 is an equidigital number, since it uses as much as digits as its factorization.
55231713100171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22050, while the sum is 37.
The spelling of 55231713100171 in words is "fifty-five trillion, two hundred thirty-one billion, seven hundred thirteen million, one hundred thousand, one hundred seventy-one".
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