55233120433 has 4 divisors (see below), whose sum is σ = 55378854640. Its totient is φ = 55087386228.

The previous prime is 55233120421. The next prime is 55233120457. The reversal of 55233120433 is 33402133255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55233120433 - 2²⁵ = 55199566001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55233120395 and 55233120404.

It is not an unprimeable number, because it can be changed into a prime (55233120413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72866535 + ... + 72867292.

It is an arithmetic number, because the mean of its divisors is an integer number (13844713660).

Almost surely, 2^55233120433 is an apocalyptic number.

It is an amenable number.

55233120433 is a deficient number, since it is larger than the sum of its proper divisors (145734207).

55233120433 is a wasteful number, since it uses less digits than its factorization.

55233120433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145734206.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 55233120433 its reverse (33402133255), we get a palindrome (88635253688).

The spelling of 55233120433 in words is "fifty-five billion, two hundred thirty-three million, one hundred twenty thousand, four hundred thirty-three".