Base | Representation |
---|---|
bin | 111110110010111101010100… |
… | …1010111110010110101111011 |
3 | 2200102202020100002002100011112 |
4 | 1331211322221113302311323 |
5 | 1034344342124322001233 |
6 | 5234435154321350535 |
7 | 224226536361446045 |
oct | 17545725127626573 |
9 | 2612666302070145 |
10 | 552361405656443 |
11 | 14aaaa17a508539 |
12 | 51b4b41119844b |
13 | 1a9295c31b6086 |
14 | 9a58612a90a95 |
15 | 43cd2c3a5d048 |
hex | 1f65ea95f2d7b |
552361405656443 has 2 divisors, whose sum is σ = 552361405656444. Its totient is φ = 552361405656442.
The previous prime is 552361405656397. The next prime is 552361405656563. The reversal of 552361405656443 is 344656504163255.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-552361405656443 is a prime.
It is not a weakly prime, because it can be changed into another prime (552361405656043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276180702828221 + 276180702828222.
It is an arithmetic number, because the mean of its divisors is an integer number (276180702828222).
Almost surely, 2552361405656443 is an apocalyptic number.
552361405656443 is a deficient number, since it is larger than the sum of its proper divisors (1).
552361405656443 is an equidigital number, since it uses as much as digits as its factorization.
552361405656443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520000, while the sum is 59.
The spelling of 552361405656443 in words is "five hundred fifty-two trillion, three hundred sixty-one billion, four hundred five million, six hundred fifty-six thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •