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552412337153 is a prime number
BaseRepresentation
bin10000000100111100101…
…01110101010000000001
31221210212120021022022212
420002132111311100001
533022320024242103
61101435201311505
754624202251125
oct10023625652001
91853776238285
10552412337153
111a33053aa116
128b089935595
1340127905a21
141ca460a5585
15e5821897d8
hex809e575401

552412337153 has 2 divisors, whose sum is σ = 552412337154. Its totient is φ = 552412337152.

The previous prime is 552412337119. The next prime is 552412337173. The reversal of 552412337153 is 351733214255.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 299008831489 + 253403505664 = 546817^2 + 503392^2 .

It is a cyclic number.

It is not a de Polignac number, because 552412337153 - 210 = 552412336129 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 552412337153.

It is not a weakly prime, because it can be changed into another prime (552412337173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276206168576 + 276206168577.

It is an arithmetic number, because the mean of its divisors is an integer number (276206168577).

Almost surely, 2552412337153 is an apocalyptic number.

It is an amenable number.

552412337153 is a deficient number, since it is larger than the sum of its proper divisors (1).

552412337153 is an equidigital number, since it uses as much as digits as its factorization.

552412337153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 378000, while the sum is 41.

The spelling of 552412337153 in words is "five hundred fifty-two billion, four hundred twelve million, three hundred thirty-seven thousand, one hundred fifty-three".