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552522301202153 = 4711755793642599
BaseRepresentation
bin111110110100001000001111…
…1011111100101111011101001
32200110022121122011102220221002
41331220100133133211323221
51034410011133101432103
65235041124023324345
7224244263461146512
oct17550203737457351
92613277564386832
10552522301202153
11150061434890417
1251b766348b06b5
131a93b824b49aa9
149a623174c1a09
1543d258de47488
hex1f6841f7e5ee9

552522301202153 has 4 divisors (see below), whose sum is σ = 564278094844800. Its totient is φ = 540766507559508.

The previous prime is 552522301202147. The next prime is 552522301202171. The reversal of 552522301202153 is 351202103225255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-552522301202153 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (552522301202143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5877896821253 + ... + 5877896821346.

It is an arithmetic number, because the mean of its divisors is an integer number (141069523711200).

Almost surely, 2552522301202153 is an apocalyptic number.

It is an amenable number.

552522301202153 is a deficient number, since it is larger than the sum of its proper divisors (11755793642647).

552522301202153 is a wasteful number, since it uses less digits than its factorization.

552522301202153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11755793642646.

The product of its (nonzero) digits is 180000, while the sum is 38.

The spelling of 552522301202153 in words is "five hundred fifty-two trillion, five hundred twenty-two billion, three hundred one million, two hundred two thousand, one hundred fifty-three".

Divisors: 1 47 11755793642599 552522301202153