Base | Representation |
---|---|
bin | 111110110100001100001000… |
… | …0101111000001101010010001 |
3 | 2200110100102011112222210110020 |
4 | 1331220120100233001222101 |
5 | 1034410130224220233431 |
6 | 5235045023512254053 |
7 | 224245010266545324 |
oct | 17550302057015221 |
9 | 2613312145883406 |
10 | 552530643524241 |
11 | 150064a25909488 |
12 | 51b781826a1329 |
13 | 1a93c554288455 |
14 | 9a628a94187bb |
15 | 43d28cb511696 |
hex | 1f68610bc1a91 |
552530643524241 has 16 divisors (see below), whose sum is σ = 744610640916480. Its totient is φ = 364409421702480.
The previous prime is 552530643524239. The next prime is 552530643524261. The reversal of 552530643524241 is 142425346035255.
It is not a de Polignac number, because 552530643524241 - 21 = 552530643524239 is a prime.
It is a super-2 number, since 2×5525306435242412 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (552530643524261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 901875951 + ... + 902488388.
It is an arithmetic number, because the mean of its divisors is an integer number (46538165057280).
Almost surely, 2552530643524241 is an apocalyptic number.
It is an amenable number.
552530643524241 is a deficient number, since it is larger than the sum of its proper divisors (192079997392239).
552530643524241 is a wasteful number, since it uses less digits than its factorization.
552530643524241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1804365436.
The product of its (nonzero) digits is 17280000, while the sum is 51.
Adding to 552530643524241 its reverse (142425346035255), we get a palindrome (694955989559496).
The spelling of 552530643524241 in words is "five hundred fifty-two trillion, five hundred thirty billion, six hundred forty-three million, five hundred twenty-four thousand, two hundred forty-one".
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