Base | Representation |
---|---|
bin | 11001001000001000111011… |
… | …00011001100110110110011 |
3 | 21020122100110101020101220222 |
4 | 30210010131203030312303 |
5 | 24220300223001430003 |
6 | 313303524511523255 |
7 | 14432026414556042 |
oct | 1444043543146663 |
9 | 236570411211828 |
10 | 55255250030003 |
11 | 16673690160071 |
12 | 6244a0752952b |
13 | 24aa717457c4a |
14 | d90522b4a559 |
15 | 65c4b103ec38 |
hex | 32411d8ccdb3 |
55255250030003 has 2 divisors, whose sum is σ = 55255250030004. Its totient is φ = 55255250030002.
The previous prime is 55255250029997. The next prime is 55255250030011. The reversal of 55255250030003 is 30003005255255.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55255250030003 - 28 = 55255250029747 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (55255250030033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27627625015001 + 27627625015002.
It is an arithmetic number, because the mean of its divisors is an integer number (27627625015002).
Almost surely, 255255250030003 is an apocalyptic number.
55255250030003 is a deficient number, since it is larger than the sum of its proper divisors (1).
55255250030003 is an equidigital number, since it uses as much as digits as its factorization.
55255250030003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112500, while the sum is 35.
Adding to 55255250030003 its reverse (30003005255255), we get a palindrome (85258255285258).
The spelling of 55255250030003 in words is "fifty-five trillion, two hundred fifty-five billion, two hundred fifty million, thirty thousand, three".
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