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55255300057 = 67824705971
BaseRepresentation
bin110011011101011110…
…001111011111011001
312021121211121002000201
4303131132033133121
51401130324100212
641214532502201
73664164205156
oct633536173731
9167554532021
1055255300057
11214851a3841
12a860a7a961
135297778529
14296268b22d
151685e2ab57
hexcdd78f7d9

55255300057 has 4 divisors (see below), whose sum is σ = 56080006096. Its totient is φ = 54430594020.

The previous prime is 55255300049. The next prime is 55255300109. The reversal of 55255300057 is 75000355255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55255300057 - 23 = 55255300049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55255299989 and 55255300025.

It is not an unprimeable number, because it can be changed into a prime (55255300157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412352919 + ... + 412353052.

It is an arithmetic number, because the mean of its divisors is an integer number (14020001524).

Almost surely, 255255300057 is an apocalyptic number.

It is an amenable number.

55255300057 is a deficient number, since it is larger than the sum of its proper divisors (824706039).

55255300057 is an equidigital number, since it uses as much as digits as its factorization.

55255300057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 824706038.

The product of its (nonzero) digits is 131250, while the sum is 37.

The spelling of 55255300057 in words is "fifty-five billion, two hundred fifty-five million, three hundred thousand, fifty-seven".

Divisors: 1 67 824705971 55255300057