Base | Representation |
---|---|
bin | 11001001000010110011100… |
… | …10111100111001000000011 |
3 | 21020200001012110000122100002 |
4 | 30210023032113213020003 |
5 | 24220410110422321103 |
6 | 313311125230550215 |
7 | 14432404360351346 |
oct | 1444131627471003 |
9 | 236601173018302 |
10 | 55262511526403 |
11 | 1667677707a865 |
12 | 62462b336836b |
13 | 24ab30399a28c |
14 | d90a112d645d |
15 | 65c7887ae488 |
hex | 3242ce5e7203 |
55262511526403 has 2 divisors, whose sum is σ = 55262511526404. Its totient is φ = 55262511526402.
The previous prime is 55262511526249. The next prime is 55262511526451. The reversal of 55262511526403 is 30462511526255.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55262511526403 is a prime.
It is a super-2 number, since 2×552625115264032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55262511526493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27631255763201 + 27631255763202.
It is an arithmetic number, because the mean of its divisors is an integer number (27631255763202).
Almost surely, 255262511526403 is an apocalyptic number.
55262511526403 is a deficient number, since it is larger than the sum of its proper divisors (1).
55262511526403 is an equidigital number, since it uses as much as digits as its factorization.
55262511526403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160000, while the sum is 47.
The spelling of 55262511526403 in words is "fifty-five trillion, two hundred sixty-two billion, five hundred eleven million, five hundred twenty-six thousand, four hundred three".
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