Base | Representation |
---|---|
bin | 110011100000001001… |
… | …111001110100010001 |
3 | 12021201222021022102002 |
4 | 303200021321310101 |
5 | 1401223334100144 |
6 | 41223221203345 |
7 | 3665251536401 |
oct | 634011716421 |
9 | 167658238362 |
10 | 55300300049 |
11 | 214a8639a15 |
12 | a873b60555 |
13 | 52a3ba2b47 |
14 | 2968642801 |
15 | 1689d6914e |
hex | ce0279d11 |
55300300049 has 2 divisors, whose sum is σ = 55300300050. Its totient is φ = 55300300048.
The previous prime is 55300300019. The next prime is 55300300067. The reversal of 55300300049 is 94000300355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28151806225 + 27148493824 = 167785^2 + 164768^2 .
It is a cyclic number.
It is not a de Polignac number, because 55300300049 - 28 = 55300299793 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55300299994 and 55300300030.
It is not a weakly prime, because it can be changed into another prime (55300300019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27650150024 + 27650150025.
It is an arithmetic number, because the mean of its divisors is an integer number (27650150025).
Almost surely, 255300300049 is an apocalyptic number.
It is an amenable number.
55300300049 is a deficient number, since it is larger than the sum of its proper divisors (1).
55300300049 is an equidigital number, since it uses as much as digits as its factorization.
55300300049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 29.
The spelling of 55300300049 in words is "fifty-five billion, three hundred million, three hundred thousand, forty-nine".
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