Base | Representation |
---|---|
bin | 111110111000011010011100… |
… | …1010010100011100000001111 |
3 | 2200112101220112200000101000111 |
4 | 1331300310321102203200033 |
5 | 1034444133110443332003 |
6 | 5240211430231140451 |
7 | 224334650532534604 |
oct | 17560647122434017 |
9 | 2615356480011014 |
10 | 553111144511503 |
11 | 150269134554116 |
12 | 5205078b214727 |
13 | 1a98220727a5a6 |
14 | 9a82a17b486ab |
15 | 43e2a545c3e6d |
hex | 1f70d394a380f |
553111144511503 has 16 divisors (see below), whose sum is σ = 568711674561024. Its totient is φ = 537682430433280.
The previous prime is 553111144511407. The next prime is 553111144511543. The reversal of 553111144511503 is 305115441111355.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-553111144511503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (553111144511543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61790053 + ... + 70172878.
It is an arithmetic number, because the mean of its divisors is an integer number (35544479660064).
Almost surely, 2553111144511503 is an apocalyptic number.
553111144511503 is a deficient number, since it is larger than the sum of its proper divisors (15600530049521).
553111144511503 is a wasteful number, since it uses less digits than its factorization.
553111144511503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131963582.
The product of its (nonzero) digits is 90000, while the sum is 40.
Adding to 553111144511503 its reverse (305115441111355), we get a palindrome (858226585622858).
The spelling of 553111144511503 in words is "five hundred fifty-three trillion, one hundred eleven billion, one hundred forty-four million, five hundred eleven thousand, five hundred three".
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