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55311714603 = 3260110225867
BaseRepresentation
bin110011100000110101…
…011100100100101011
312021202202202020020100
4303200311130210223
51401234244331403
641224310000443
73665450550105
oct634065344453
9167682666210
1055311714603
1121504025932
12a877946123
1352a636b512
142969d74575
15168ad712a3
hexce0d5c92b

55311714603 has 12 divisors (see below), whose sum is σ = 80027642968. Its totient is φ = 36813117600.

The previous prime is 55311714581. The next prime is 55311714677. The reversal of 55311714603 is 30641711355.

55311714603 is a `hidden beast` number, since 5 + 5 + 31 + 1 + 7 + 14 + 603 = 666.

55311714603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 55311714603 - 28 = 55311714347 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55311714203) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5107525 + ... + 5118342.

Almost surely, 255311714603 is an apocalyptic number.

55311714603 is a deficient number, since it is larger than the sum of its proper divisors (24715928365).

55311714603 is a wasteful number, since it uses less digits than its factorization.

55311714603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10226474 (or 10226471 counting only the distinct ones).

The product of its (nonzero) digits is 37800, while the sum is 36.

The spelling of 55311714603 in words is "fifty-five billion, three hundred eleven million, seven hundred fourteen thousand, six hundred three".

Divisors: 1 3 9 601 1803 5409 10225867 30677601 92032803 6145746067 18437238201 55311714603