Base | Representation |
---|---|
bin | 101000001111101010110… |
… | …0001001110001000110001 |
3 | 201120210000012100111110102 |
4 | 1100133111201032020301 |
5 | 1211110402010244432 |
6 | 15433000042442145 |
7 | 1110421264111655 |
oct | 120372541161061 |
9 | 21523005314412 |
10 | 5531205165617 |
11 | 184285313282a |
12 | 753b99503355 |
13 | 31178a189881 |
14 | 1519d70caa65 |
15 | 98d2cb89962 |
hex | 507d584e231 |
5531205165617 has 2 divisors, whose sum is σ = 5531205165618. Its totient is φ = 5531205165616.
The previous prime is 5531205165589. The next prime is 5531205165623. The reversal of 5531205165617 is 7165615021355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3240489618496 + 2290715547121 = 1800136^2 + 1513511^2 .
It is a cyclic number.
It is not a de Polignac number, because 5531205165617 - 220 = 5531204117041 is a prime.
It is not a weakly prime, because it can be changed into another prime (5531205165817) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2765602582808 + 2765602582809.
It is an arithmetic number, because the mean of its divisors is an integer number (2765602582809).
Almost surely, 25531205165617 is an apocalyptic number.
It is an amenable number.
5531205165617 is a deficient number, since it is larger than the sum of its proper divisors (1).
5531205165617 is an equidigital number, since it uses as much as digits as its factorization.
5531205165617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 945000, while the sum is 47.
The spelling of 5531205165617 in words is "five trillion, five hundred thirty-one billion, two hundred five million, one hundred sixty-five thousand, six hundred seventeen".
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