Base | Representation |
---|---|
bin | 110011100000110111… |
… | …010101110010111011 |
3 | 12021202210200110100021 |
4 | 303200313111302323 |
5 | 1401234411224011 |
6 | 41224324351311 |
7 | 3665455015522 |
oct | 634067256273 |
9 | 167683613307 |
10 | 55312211131 |
11 | 21504334991 |
12 | a877b45537 |
13 | 52a64b3518 |
14 | 296a0634b9 |
15 | 168ae1d471 |
hex | ce0dd5cbb |
55312211131 has 2 divisors, whose sum is σ = 55312211132. Its totient is φ = 55312211130.
The previous prime is 55312211081. The next prime is 55312211137. The reversal of 55312211131 is 13111221355.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55312211131 - 29 = 55312210619 is a prime.
It is a super-2 number, since 2×553122111312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55312211096 and 55312211105.
It is not a weakly prime, because it can be changed into another prime (55312211137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27656105565 + 27656105566.
It is an arithmetic number, because the mean of its divisors is an integer number (27656105566).
Almost surely, 255312211131 is an apocalyptic number.
55312211131 is a deficient number, since it is larger than the sum of its proper divisors (1).
55312211131 is an equidigital number, since it uses as much as digits as its factorization.
55312211131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 900, while the sum is 25.
Adding to 55312211131 its reverse (13111221355), we get a palindrome (68423432486).
The spelling of 55312211131 in words is "fifty-five billion, three hundred twelve million, two hundred eleven thousand, one hundred thirty-one".
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