Base | Representation |
---|---|
bin | 11001001001111001101000… |
… | …11111011111010100101001 |
3 | 21020212010122201211201210011 |
4 | 30210330310133133110221 |
5 | 24222243141201201202 |
6 | 313351413354251521 |
7 | 14436301132062643 |
oct | 1444746437372451 |
9 | 236763581751704 |
10 | 55315764475177 |
11 | 16697313a70428 |
12 | 6254695726ba1 |
13 | 24b333c65715b |
14 | d93423a75893 |
15 | 65dd53a10bd7 |
hex | 324f347df529 |
55315764475177 has 2 divisors, whose sum is σ = 55315764475178. Its totient is φ = 55315764475176.
The previous prime is 55315764475157. The next prime is 55315764475253. The reversal of 55315764475177 is 77157446751355.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55141154152681 + 174610322496 = 7425709^2 + 417864^2 .
It is a cyclic number.
It is not a de Polignac number, because 55315764475177 - 211 = 55315764473129 is a prime.
It is not a weakly prime, because it can be changed into another prime (55315764475157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27657882237588 + 27657882237589.
It is an arithmetic number, because the mean of its divisors is an integer number (27657882237589).
Almost surely, 255315764475177 is an apocalyptic number.
It is an amenable number.
55315764475177 is a deficient number, since it is larger than the sum of its proper divisors (1).
55315764475177 is an equidigital number, since it uses as much as digits as its factorization.
55315764475177 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432180000, while the sum is 67.
The spelling of 55315764475177 in words is "fifty-five trillion, three hundred fifteen billion, seven hundred sixty-four million, four hundred seventy-five thousand, one hundred seventy-seven".
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