Base | Representation |
---|---|
bin | 11001001001111100011000… |
… | …00010001111010011011010 |
3 | 21020212021110002111210202111 |
4 | 30210332030002033103122 |
5 | 24222304143144434034 |
6 | 313352215222222534 |
7 | 14436352415051332 |
oct | 1444761402172332 |
9 | 236767402453674 |
10 | 55317233202394 |
11 | 166979a8030979 |
12 | 6254a25584a4a |
13 | 24b3514a1a007 |
14 | d93522b580c2 |
15 | 65dddc92e364 |
hex | 324f8c08f4da |
55317233202394 has 4 divisors (see below), whose sum is σ = 82975849803594. Its totient is φ = 27658616601196.
The previous prime is 55317233202373. The next prime is 55317233202397. The reversal of 55317233202394 is 49320233271355.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 53891088513025 + 1426144689369 = 7341055^2 + 1194213^2 .
It is not an unprimeable number, because it can be changed into a prime (55317233202397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13829308300597 + ... + 13829308300600.
Almost surely, 255317233202394 is an apocalyptic number.
55317233202394 is a deficient number, since it is larger than the sum of its proper divisors (27658616601200).
55317233202394 is a wasteful number, since it uses less digits than its factorization.
55317233202394 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27658616601199.
The product of its (nonzero) digits is 4082400, while the sum is 49.
The spelling of 55317233202394 in words is "fifty-five trillion, three hundred seventeen billion, two hundred thirty-three million, two hundred two thousand, three hundred ninety-four".
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