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55317233202449 is a prime number
BaseRepresentation
bin11001001001111100011000…
…00010001111010100010001
321020212021110002111210211112
430210332030002033110101
524222304143144434244
6313352215222223105
714436352415051441
oct1444761402172421
9236767402453745
1055317233202449
11166979a8030a19
126254a25584a95
1324b3514a1a04a
14d93522b58121
1565dddc92e39e
hex324f8c08f511

55317233202449 has 2 divisors, whose sum is σ = 55317233202450. Its totient is φ = 55317233202448.

The previous prime is 55317233202421. The next prime is 55317233202481. The reversal of 55317233202449 is 94420233271355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47800533646849 + 7516699555600 = 6913793^2 + 2741660^2 .

It is a cyclic number.

It is not a de Polignac number, because 55317233202449 - 228 = 55316964766993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55317233202397 and 55317233202406.

It is not a weakly prime, because it can be changed into another prime (55317233202419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27658616601224 + 27658616601225.

It is an arithmetic number, because the mean of its divisors is an integer number (27658616601225).

Almost surely, 255317233202449 is an apocalyptic number.

It is an amenable number.

55317233202449 is a deficient number, since it is larger than the sum of its proper divisors (1).

55317233202449 is an equidigital number, since it uses as much as digits as its factorization.

55317233202449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 50.

The spelling of 55317233202449 in words is "fifty-five trillion, three hundred seventeen billion, two hundred thirty-three million, two hundred two thousand, four hundred forty-nine".