Base | Representation |
---|---|
bin | 101000010000000110110… |
… | …0001101010000010100001 |
3 | 201120212102200110002000001 |
4 | 1100200031201222002201 |
5 | 1211114313032212001 |
6 | 15433233210300001 |
7 | 1110453463651324 |
oct | 120401541520241 |
9 | 21525380402001 |
10 | 5532144804001 |
11 | 1843195578a82 |
12 | 754200127601 |
13 | 3118a9a5130a |
14 | 151a85c047bb |
15 | 98d853e6001 |
hex | 5080d86a0a1 |
5532144804001 has 2 divisors, whose sum is σ = 5532144804002. Its totient is φ = 5532144804000.
The previous prime is 5532144803963. The next prime is 5532144804037. The reversal of 5532144804001 is 1004084412355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4466666675601 + 1065478128400 = 2113449^2 + 1032220^2 .
It is a cyclic number.
It is not a de Polignac number, because 5532144804001 - 219 = 5532144279713 is a prime.
It is a super-2 number, since 2×55321448040012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5532144804301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766072402000 + 2766072402001.
It is an arithmetic number, because the mean of its divisors is an integer number (2766072402001).
Almost surely, 25532144804001 is an apocalyptic number.
It is an amenable number.
5532144804001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5532144804001 is an equidigital number, since it uses as much as digits as its factorization.
5532144804001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 37.
The spelling of 5532144804001 in words is "five trillion, five hundred thirty-two billion, one hundred forty-four million, eight hundred four thousand, one".
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