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5532154443001 is a prime number
BaseRepresentation
bin101000010000000111000…
…0110011011010011111001
3201120212110100120210020001
41100200032012123103321
51211114323014134001
615433234153033001
71110453641615344
oct120401606332371
921525410523201
105532154443001
11184319aa6199a
127542033b5761
133118aba47774
14151a871d345b
1598d8619c001
hex5080e19b4f9

5532154443001 has 2 divisors, whose sum is σ = 5532154443002. Its totient is φ = 5532154443000.

The previous prime is 5532154442993. The next prime is 5532154443071. The reversal of 5532154443001 is 1003444512355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5420985546601 + 111168896400 = 2328301^2 + 333420^2 .

It is a cyclic number.

It is not a de Polignac number, because 5532154443001 - 23 = 5532154442993 is a prime.

It is not a weakly prime, because it can be changed into another prime (5532154443071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766077221500 + 2766077221501.

It is an arithmetic number, because the mean of its divisors is an integer number (2766077221501).

Almost surely, 25532154443001 is an apocalyptic number.

It is an amenable number.

5532154443001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5532154443001 is an equidigital number, since it uses as much as digits as its factorization.

5532154443001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 5532154443001 its reverse (1003444512355), we get a palindrome (6535598955356).

The spelling of 5532154443001 in words is "five trillion, five hundred thirty-two billion, one hundred fifty-four million, four hundred forty-three thousand, one".