Base | Representation |
---|---|
bin | 10000000110101011111… |
… | …00000111011111001011 |
3 | 1221220021120110121010020 |
4 | 20003111330013133023 |
5 | 33031222322321303 |
6 | 1102111522151523 |
7 | 54656256626211 |
oct | 10032574073713 |
9 | 1856246417106 |
10 | 553345120203 |
11 | 1a37439928a7 |
12 | 8b2aa1b25a3 |
13 | 40245c3a065 |
14 | 1cad3d16cb1 |
15 | e5d8edea53 |
hex | 80d5f077cb |
553345120203 has 8 divisors (see below), whose sum is σ = 757733858448. Its totient is φ = 358926564384.
The previous prime is 553345120171. The next prime is 553345120217. The reversal of 553345120203 is 302021543355.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 553345120203 - 25 = 553345120171 is a prime.
It is a super-2 number, since 2×5533451202032 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (553345120283) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2492545476 + ... + 2492545697.
It is an arithmetic number, because the mean of its divisors is an integer number (94716732306).
Almost surely, 2553345120203 is an apocalyptic number.
553345120203 is a deficient number, since it is larger than the sum of its proper divisors (204388738245).
553345120203 is a wasteful number, since it uses less digits than its factorization.
553345120203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4985091213.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 553345120203 its reverse (302021543355), we get a palindrome (855366663558).
The spelling of 553345120203 in words is "five hundred fifty-three billion, three hundred forty-five million, one hundred twenty thousand, two hundred three".
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