Base | Representation |
---|---|
bin | 11001001010011101101011… |
… | …01100110101111010101011 |
3 | 21020220222121002211012021022 |
4 | 30211032311230311322223 |
5 | 24223102302144340033 |
6 | 313404333301203055 |
7 | 14440554443163566 |
oct | 1445166554657253 |
9 | 236828532735238 |
10 | 55335112105643 |
11 | 166a4542222577 |
12 | 625839510048b |
13 | 24b5103b2b3c6 |
14 | d9433b4614dd |
15 | 65e5d7367098 |
hex | 3253b5b35eab |
55335112105643 has 2 divisors, whose sum is σ = 55335112105644. Its totient is φ = 55335112105642.
The previous prime is 55335112105619. The next prime is 55335112105747. The reversal of 55335112105643 is 34650121153355.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55335112105643 - 28 = 55335112105387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55335112105594 and 55335112105603.
It is not a weakly prime, because it can be changed into another prime (55335112105613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27667556052821 + 27667556052822.
It is an arithmetic number, because the mean of its divisors is an integer number (27667556052822).
Almost surely, 255335112105643 is an apocalyptic number.
55335112105643 is a deficient number, since it is larger than the sum of its proper divisors (1).
55335112105643 is an equidigital number, since it uses as much as digits as its factorization.
55335112105643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810000, while the sum is 44.
Adding to 55335112105643 its reverse (34650121153355), we get a palindrome (89985233258998).
The spelling of 55335112105643 in words is "fifty-five trillion, three hundred thirty-five billion, one hundred twelve million, one hundred five thousand, six hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •