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553413153642 = 23242819379853
BaseRepresentation
bin10000000110110011111…
…11101001001101101010
31221220110022111001110020
420003121333221031222
533031342231404032
61102122352301310
754661044122346
oct10033177511552
91856408431406
10553413153642
111a3779330388
128b308b41836
134025706a72b
141cadcd86626
15e5dee7cb2c
hex80d9fe936a

553413153642 has 16 divisors (see below), whose sum is σ = 1106833779360. Its totient is φ = 184469805872.

The previous prime is 553413153547. The next prime is 553413153679. The reversal of 553413153642 is 246351314355.

It is a happy number.

It is a super-2 number, since 2×5534131536422 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 553413153594 and 553413153603.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1266988 + ... + 1646840.

It is an arithmetic number, because the mean of its divisors is an integer number (69177111210).

Almost surely, 2553413153642 is an apocalyptic number.

553413153642 is an abundant number, since it is smaller than the sum of its proper divisors (553420625718).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

553413153642 is a wasteful number, since it uses less digits than its factorization.

553413153642 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 622677.

The product of its digits is 648000, while the sum is 42.

Adding to 553413153642 its reverse (246351314355), we get a palindrome (799764467997).

The spelling of 553413153642 in words is "five hundred fifty-three billion, four hundred thirteen million, one hundred fifty-three thousand, six hundred forty-two".

Divisors: 1 2 3 6 242819 379853 485638 728457 759706 1139559 1456914 2279118 92235525607 184471051214 276706576821 553413153642