Base | Representation |
---|---|
bin | 110011100010101101… |
… | …010001001110011001 |
3 | 12021211221212001202020 |
4 | 303202231101032121 |
5 | 1401320320003101 |
6 | 41231351125053 |
7 | 3666311542554 |
oct | 634255211631 |
9 | 167757761666 |
10 | 55343125401 |
11 | 2151a82a273 |
12 | a886373789 |
13 | 52aca186a5 |
14 | 29701cd69b |
15 | 168d9c8136 |
hex | ce2b51399 |
55343125401 has 8 divisors (see below), whose sum is σ = 74051580000. Its totient is φ = 36765043872.
The previous prime is 55343125339. The next prime is 55343125421. The reversal of 55343125401 is 10452134355.
55343125401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55343125401 - 215 = 55343092633 is a prime.
It is a super-2 number, since 2×553431254012 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (55343125421) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32592276 + ... + 32593973.
It is an arithmetic number, because the mean of its divisors is an integer number (9256447500).
Almost surely, 255343125401 is an apocalyptic number.
It is an amenable number.
55343125401 is a deficient number, since it is larger than the sum of its proper divisors (18708454599).
55343125401 is a wasteful number, since it uses less digits than its factorization.
55343125401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65186535.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 55343125401 its reverse (10452134355), we get a palindrome (65795259756).
The spelling of 55343125401 in words is "fifty-five billion, three hundred forty-three million, one hundred twenty-five thousand, four hundred one".
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