Base | Representation |
---|---|
bin | 11001001010101100101001… |
… | …11011000111101101011011 |
3 | 21020221202100102120000010111 |
4 | 30211112110323013231123 |
5 | 24223220233421310003 |
6 | 313412143151025151 |
7 | 14441260621253455 |
oct | 1445262473075533 |
9 | 236852312500114 |
10 | 55343152135003 |
11 | 166a7998650637 |
12 | 6259a5980b1b7 |
13 | 24b5ab5748525 |
14 | d948a11892d5 |
15 | 65e90811ce6d |
hex | 325594ec7b5b |
55343152135003 has 4 divisors (see below), whose sum is σ = 56043698364640. Its totient is φ = 54642605905368.
The previous prime is 55343152134983. The next prime is 55343152135043. The reversal of 55343152135003 is 30053125134355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55343152135003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55343152135043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350273114700 + ... + 350273114857.
It is an arithmetic number, because the mean of its divisors is an integer number (14010924591160).
Almost surely, 255343152135003 is an apocalyptic number.
55343152135003 is a deficient number, since it is larger than the sum of its proper divisors (700546229637).
55343152135003 is an equidigital number, since it uses as much as digits as its factorization.
55343152135003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 700546229636.
The product of its (nonzero) digits is 405000, while the sum is 40.
Adding to 55343152135003 its reverse (30053125134355), we get a palindrome (85396277269358).
The spelling of 55343152135003 in words is "fifty-five trillion, three hundred forty-three billion, one hundred fifty-two million, one hundred thirty-five thousand, three".
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