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55343152135003 = 79700546229557
BaseRepresentation
bin11001001010101100101001…
…11011000111101101011011
321020221202100102120000010111
430211112110323013231123
524223220233421310003
6313412143151025151
714441260621253455
oct1445262473075533
9236852312500114
1055343152135003
11166a7998650637
126259a5980b1b7
1324b5ab5748525
14d948a11892d5
1565e90811ce6d
hex325594ec7b5b

55343152135003 has 4 divisors (see below), whose sum is σ = 56043698364640. Its totient is φ = 54642605905368.

The previous prime is 55343152134983. The next prime is 55343152135043. The reversal of 55343152135003 is 30053125134355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55343152135003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55343152135043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350273114700 + ... + 350273114857.

It is an arithmetic number, because the mean of its divisors is an integer number (14010924591160).

Almost surely, 255343152135003 is an apocalyptic number.

55343152135003 is a deficient number, since it is larger than the sum of its proper divisors (700546229637).

55343152135003 is an equidigital number, since it uses as much as digits as its factorization.

55343152135003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 700546229636.

The product of its (nonzero) digits is 405000, while the sum is 40.

Adding to 55343152135003 its reverse (30053125134355), we get a palindrome (85396277269358).

The spelling of 55343152135003 in words is "fifty-five trillion, three hundred forty-three billion, one hundred fifty-two million, one hundred thirty-five thousand, three".

Divisors: 1 79 700546229557 55343152135003