Base | Representation |
---|---|
bin | 11001001010111011101110… |
… | …01001001010011010011011 |
3 | 21020222112020020212210020121 |
4 | 30211131313021022122123 |
5 | 24223333321030343303 |
6 | 313420002034134111 |
7 | 14441665246543552 |
oct | 1445356711123233 |
9 | 236875206783217 |
10 | 55351242434203 |
11 | 1670036a394121 |
12 | 625b537121337 |
13 | 24b67a48b6811 |
14 | d9502b83ad99 |
15 | 65ec2d5039bd |
hex | 32577724a69b |
55351242434203 has 2 divisors, whose sum is σ = 55351242434204. Its totient is φ = 55351242434202.
The previous prime is 55351242434179. The next prime is 55351242434297. The reversal of 55351242434203 is 30243424215355.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55351242434203 - 29 = 55351242433691 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55351242434203.
It is not a weakly prime, because it can be changed into another prime (55351942434203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27675621217101 + 27675621217102.
It is an arithmetic number, because the mean of its divisors is an integer number (27675621217102).
Almost surely, 255351242434203 is an apocalyptic number.
55351242434203 is a deficient number, since it is larger than the sum of its proper divisors (1).
55351242434203 is an equidigital number, since it uses as much as digits as its factorization.
55351242434203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728000, while the sum is 43.
Adding to 55351242434203 its reverse (30243424215355), we get a palindrome (85594666649558).
The spelling of 55351242434203 in words is "fifty-five trillion, three hundred fifty-one billion, two hundred forty-two million, four hundred thirty-four thousand, two hundred three".
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