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553543502131 = 12711513786803
BaseRepresentation
bin10000000111000011100…
…00111000100100110011
31221220210101202102222001
420003201300320210303
533032124114032011
61102143330154431
754664216064164
oct10034160704463
91856711672861
10553543502131
111a3835970104
128b344722a17
1340278078a09
141cb123d776b
15e5eb6297c1
hex80e1c38933

553543502131 has 8 divisors (see below), whose sum is σ = 558386970624. Its totient is φ = 548707609800.

The previous prime is 553543502047. The next prime is 553543502153. The reversal of 553543502131 is 131205345355.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 553543502131 - 213 = 553543493939 is a prime.

It is a super-2 number, since 2×5535435021312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (553543503131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1747225 + ... + 2039578.

It is an arithmetic number, because the mean of its divisors is an integer number (69798371328).

Almost surely, 2553543502131 is an apocalyptic number.

553543502131 is a deficient number, since it is larger than the sum of its proper divisors (4843468493).

553543502131 is a wasteful number, since it uses less digits than its factorization.

553543502131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3788081.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 553543502131 its reverse (131205345355), we get a palindrome (684748847486).

The spelling of 553543502131 in words is "five hundred fifty-three billion, five hundred forty-three million, five hundred two thousand, one hundred thirty-one".

Divisors: 1 127 1151 146177 3786803 480923981 4358610253 553543502131