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55372003426121 = 161833421615487
BaseRepresentation
bin11001001011100010011001…
…00110000011111101001001
321021001111211010100110011012
430211301030212003331021
524224203330334113441
6313433314110213305
714443331602220024
oct1445611446037511
9237044733313135
1055372003426121
1116709153430688
12626356bab4235
1324b8732b37115
14d9603ac161bb
15660545e8d9eb
hex325c4c983f49

55372003426121 has 4 divisors (see below), whose sum is σ = 55375425057792. Its totient is φ = 55368581794452.

The previous prime is 55372003426039. The next prime is 55372003426127. The reversal of 55372003426121 is 12162430027355.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55372003426121 - 234 = 55354823556937 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55372003426127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1710791561 + ... + 1710823926.

It is an arithmetic number, because the mean of its divisors is an integer number (13843856264448).

Almost surely, 255372003426121 is an apocalyptic number.

It is an amenable number.

55372003426121 is a deficient number, since it is larger than the sum of its proper divisors (3421631671).

55372003426121 is a wasteful number, since it uses less digits than its factorization.

55372003426121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3421631670.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 55372003426121 in words is "fifty-five trillion, three hundred seventy-two billion, three million, four hundred twenty-six thousand, one hundred twenty-one".

Divisors: 1 16183 3421615487 55372003426121