Base | Representation |
---|---|
bin | 110011100110001011… |
… | …001100001000010101 |
3 | 12022000000022122222120 |
4 | 303212023030020111 |
5 | 1401430213104001 |
6 | 41241230050153 |
7 | 4000616166351 |
oct | 634613141025 |
9 | 168000278876 |
10 | 55401300501 |
11 | 2154a654068 |
12 | a8a1949959 |
13 | 52bbaa6b21 |
14 | 2977c14461 |
15 | 1693b6a236 |
hex | ce62cc215 |
55401300501 has 16 divisors (see below), whose sum is σ = 75092360448. Its totient is φ = 36322430400.
The previous prime is 55401300481. The next prime is 55401300509. The reversal of 55401300501 is 10500310455.
It is not a de Polignac number, because 55401300501 - 25 = 55401300469 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55401300509) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1186171 + ... + 1231991.
It is an arithmetic number, because the mean of its divisors is an integer number (4693272528).
Almost surely, 255401300501 is an apocalyptic number.
It is an amenable number.
55401300501 is a deficient number, since it is larger than the sum of its proper divisors (19691059947).
55401300501 is a wasteful number, since it uses less digits than its factorization.
55401300501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52492.
The product of its (nonzero) digits is 1500, while the sum is 24.
Adding to 55401300501 its reverse (10500310455), we get a palindrome (65901610956).
The spelling of 55401300501 in words is "fifty-five billion, four hundred one million, three hundred thousand, five hundred one".
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