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55401433 = 311787143
BaseRepresentation
bin1101001101010…
…1101111011001
310212020200110221
43103111233121
5103140321213
65255240041
71241622133
oct323255731
9125220427
1055401433
11292aaa0a
1216679021
13b629b19
147502053
154ce538d
hex34d5bd9

55401433 has 4 divisors (see below), whose sum is σ = 57188608. Its totient is φ = 53614260.

The previous prime is 55401431. The next prime is 55401439. The reversal of 55401433 is 33410455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55401433 - 21 = 55401431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55401398 and 55401407.

It is not an unprimeable number, because it can be changed into a prime (55401431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893541 + ... + 893602.

It is an arithmetic number, because the mean of its divisors is an integer number (14297152).

Almost surely, 255401433 is an apocalyptic number.

It is an amenable number.

55401433 is a deficient number, since it is larger than the sum of its proper divisors (1787175).

55401433 is a wasteful number, since it uses less digits than its factorization.

55401433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1787174.

The product of its (nonzero) digits is 3600, while the sum is 25.

The square root of 55401433 is about 7443.2138891745. The cubic root of 55401433 is about 381.2182348165.

Adding to 55401433 its reverse (33410455), we get a palindrome (88811888).

The spelling of 55401433 in words is "fifty-five million, four hundred one thousand, four hundred thirty-three".

Divisors: 1 31 1787143 55401433