Base | Representation |
---|---|
bin | 110011100111101001… |
… | …111010110100100001 |
3 | 12022001202001022011011 |
4 | 303213221322310201 |
5 | 1402003042231111 |
6 | 41243514220521 |
7 | 4001340234211 |
oct | 634751726441 |
9 | 168052038134 |
10 | 55426133281 |
11 | 21562675322 |
12 | a8aa124741 |
13 | 52c3c8cb8c |
14 | 297b23a241 |
15 | 1695e23021 |
hex | ce7a7ad21 |
55426133281 has 2 divisors, whose sum is σ = 55426133282. Its totient is φ = 55426133280.
The previous prime is 55426133131. The next prime is 55426133299. The reversal of 55426133281 is 18233162455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48627306256 + 6798827025 = 220516^2 + 82455^2 .
It is a cyclic number.
It is not a de Polignac number, because 55426133281 - 225 = 55392578849 is a prime.
It is a super-2 number, since 2×554261332812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55426133381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27713066640 + 27713066641.
It is an arithmetic number, because the mean of its divisors is an integer number (27713066641).
Almost surely, 255426133281 is an apocalyptic number.
It is an amenable number.
55426133281 is a deficient number, since it is larger than the sum of its proper divisors (1).
55426133281 is an equidigital number, since it uses as much as digits as its factorization.
55426133281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 172800, while the sum is 40.
The spelling of 55426133281 in words is "fifty-five billion, four hundred twenty-six million, one hundred thirty-three thousand, two hundred eighty-one".
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