Base | Representation |
---|---|
bin | 11001001101010000011110… |
… | …11010111101000011101011 |
3 | 21021021011101010111010012011 |
4 | 30212220033122331003223 |
5 | 24231140401300140001 |
6 | 313520410541300351 |
7 | 14450523332260120 |
oct | 1446501732750353 |
9 | 237234333433164 |
10 | 55431106646251 |
11 | 16731222685756 |
12 | 6272b055646b7 |
13 | 24c119185751b |
14 | d98c4654a747 |
15 | 661d54aedd51 |
hex | 326a0f6bd0eb |
55431106646251 has 8 divisors (see below), whose sum is σ = 63753338309600. Its totient is φ = 47209750518528.
The previous prime is 55431106646233. The next prime is 55431106646257. The reversal of 55431106646251 is 15264660113455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55431106646251 - 233 = 55422516711659 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55431106646195 and 55431106646204.
It is not an unprimeable number, because it can be changed into a prime (55431106646257) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25218882726 + ... + 25218884923.
It is an arithmetic number, because the mean of its divisors is an integer number (7969167288700).
Almost surely, 255431106646251 is an apocalyptic number.
55431106646251 is a deficient number, since it is larger than the sum of its proper divisors (8322231663349).
55431106646251 is a wasteful number, since it uses less digits than its factorization.
55431106646251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50437767813.
The product of its (nonzero) digits is 2592000, while the sum is 49.
The spelling of 55431106646251 in words is "fifty-five trillion, four hundred thirty-one billion, one hundred six million, six hundred forty-six thousand, two hundred fifty-one".
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